m = 1 n = 0 for i in range(3): m += 1 for j in range(5): n += 1 print(m, n) |
请回答下列问题:
Const n = 12
Dim a(1 To n) As Integer, mc(1 To n) As Integer
Private Sub Command1_Click()
’n个用户的ID依次为1到n,读取n个用户的积分和排名数据分别存储到数组a和数组mc中,并在列表框List1中显示ID、积分、积分排名,代码略
End Sub
Private Sub Command2_Click()
Dim i As Integer, j As Integer, k As Integer, d As Integer
Dim s As String, flag As Boolean, x As Integer, y As Integer
Dim p(1 To 20) As Integer '存储输入的ID和积分增值,每次输入不超过10组
For i = 1 To 20
p(i) = 0
Next i
s = Text1.Text
d = 0: k = 0
For i = 1 To Len(s)
If Mid(s, i, 1) = "," Then
If flag Then
x = Val(Mid(s, i - d, d))
For j = 1 To k Step 2
If p(j) = x Then Exit For
Next j
If j > k Then
p(j) = x: k = k + 2
End If
Else
y = Val(Mid(s, i - d, d))
p(j + 1) = p(j + 1) + y
End If
flag = Not flag: d = 0
Else
End If
Next i
For i = 1 To k \ 2
x = p(2 * i - 1): y = p(2 * i)
mc(x) = 1
For j = 1 To n
If j <> x Then
If a(j) < a(x) + y And a(j) >= a(x) Then
End If
If a(j) > a(x) + y Then mc(x) = mc(x) + 1
Next j
Next i
'在列表框List2中显示ID,积分、排名,代码略
End Sub
s = s + Str(f(i))
If i Mod n = 0 Then
List1.AddItem s
s=""
End If
For j = 1 To n
k = (n + 1) * ((i-l) Mod 2)+(-1)^(i-1)*j
If
b(2 * w - 1) = i: b(2 * w) = k
w = w + 1
End If
Next j
For j=i+1 To m
If length > maxlen Then maxlen = length
Next j
i = i + 1
以下说法正确的是
A.可以使用GoldWave的淡入功能实现音乐音量逐渐变大
B.把音乐另存为WAV格式的文件,音质会比原来的好
C.当前状态下执行“删除”命令,则该音乐变成单声道格式
D.在媒体元素分解表中需要记录该背景音乐文件的名称和处理工具
E.该音乐每秒播放的数据量为128kb
A.测试场景时,一直能听到背景音乐,则声音同步方式可能为“事件”
B.为实现“激光技术”图层第11帧到20帧的淡入动画效果,可把该图层第11帧中的图形实例Alpha值设为100%
C.“高铁”图层展示的是高铁位图实例向右移动的动画,则其动画类型是动画补间
D.“量子技术”图层第10帧上有动作脚本“stop();”,把该作品导出为AVI格式的影片,该影片播放到第10帧会自动停止
上述程序段中方框处可选语句为:
则(1)(2)(3)处的语句依次为( )
A.①②③ | B.①③② | C.②①③ | D.③②① |
count = count + 1
If i+k-1 <= Len(s) And flag Then
Else
ns= ns + Mid(s,i,1)
i = i + 1
End If
If count = k Then
count = 0
If flag = True Then
End If
A.①ns = ns + Mid(s,i+k–count,1) ②i=i+k ③flag = Not flag |
B.①ns = ns + Mid(s,i+k–count,1) ②i=i+1 ③flag = False |
C.①ns = ns + Mid(s,i+k-1,1) ②i=i+k ③flag = Not flag |
D.①ns = ns + Mid(s,i+k-1,1) ②i=i+1 ③flag = False |
数组元素a(1)到a(10)的值依次为“7,9,12,12,19,28,32,34,34,40 ”,执行该程序段后,变量i和m的值可能的是( )
A.1 4 | B.2 8 | C.3 6 | D.5 7 |
m= (i+ j)\ 2
cnt = cnt + l
If a(m) = Key Then flag = False
If a(m) < Key Then
i = m + l
Elself flag Then
j = m – l
End If
A.5 | B.13 | C.39 | D.40 |