学进去-教育应平等而普惠
试题
类型:阅读理解
难度系数:0.85
所属科目:高中英语

There is a mountain of great ski opportunities not too far from Boston. Road-trip to one of these fantastic ski mountains this winter.

Blue Hills Ski Area

A ski day trip doesn’t get any easier than the Blue Hills Ski Area. It is the only snow sports facility in the metro area. Skiing and snowboarding are spread over its 60 skiable acres, 90% of which are equipped for snowmaking. The vertical drop is 309 feet and there are four lifts serving the 16 trails, most of which are for advanced skiers. There are lessons for kids and adults to help you get there.

Crochet Mountain Resort

It’s famous for signature “Midnight Madness” events and daily night skiing. It has an 875-foot vertical drop and 23 trails across 75 skiable acres. A great mountain for skiers, half its terrain is graded for intermediates with the rest being split between advanced and beginner terrain.

Jiminy Peak Mountain Resort

It’s the only one of ski resorts to be 100% powered by renewable energy sources. Skiers will find a 1,150-foot vertical drop, 45 trails, 3 terrain parks and 9 lifts across 167 skiable acres. The whole family can take lessons, enjoy dining or buy a ticket and go for a ride on the 3,600-foot Mountain Coaster!

Smugglers’ Notch

Smugglers’ Notch has a 2,564-foot vertical drop, 78 trails, 5 terrain parks and 8 lifts spread across 1,000 skiable acres. Known as a full-service family-oriented resort, it offers plenty to do off mountain like ice skating, arts and crafts workshops and an indoor swimming pool!

1.Which ski resort mainly targets advanced skiers?
A.Blue Hills Ski Area.B.Crochet Mountain Resort.
C.Jiminy Peak Mountain Resort.D.Smugglers’ Notch.
2.What’s the highlight of Jiminy Peak Mountain Resort?
A.Its trails.B.Its location.
C.Its vertical drop.D.Its green concept.
3.What can skiers do in Smugglers’ Notch?
A.Have a swim.B.Ski with world champions.
C.Enjoy stone sculptures.D.Ride a roller coaster.
编辑解析赚收入
收藏
|
有奖纠错

同类型试题

优质答疑

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

用户名称
2019-09-19

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

用户名称
2019-09-19
我要答疑
编写解析
解析:

奖学金将在审核通过后自动发放到帐

提交
我要答疑
我要答疑:
提交