
编写程序,计算修改括号序列使其配对的最少次数。部分Python程序如下,请在划线处填入合适的代码。
s=input() #输入括号序列,序列中仅包含“(”、“)”两种字符,且长度为偶数
x=0
ans=0
for i in range(len(s)):
if s[i]=="(":
①
elif s[i]==")" and x>=1:
x-=1
elif s[i]==")" and ②
ans+=1
x+=1
ans+=③
print(ans)

同类型试题

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2


y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

