搜索
a=[5,10,21,7,24,14,9,11,36,37]
n=len(a) ;b=[0]*n
num=0;k=0
while k <10:
if ① :
b[num]=a[k]
num+=1
else:
②
k+=1
for j in range(n-num,n):
③
print(a)
| A．①a[k]%2==1 ②a[k-num]=a[k] ③a[j]=b[j-n+num] |
| B．①a[k]%2==0 ②b[k-num]=a[k] ③a[j]=b[j+num] |
| C．①a[k]%2==0 ②a[k-num]=a[k] ③a[j]=b[j+num] |
| D．①a[k]%2==1 ②b[k-num]=a[k] ③a[j]=b[j-n+num] |
同类型试题
y = sin x， x∈R， y∈[–1，1]，周期为2π，函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x， x∈[–1，1]， y∈[–π/2，π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2
y = sin x， x∈R， y∈[–1，1]，周期为2π，函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x， x∈[–1，1]， y∈[–π/2，π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2
