学进去-教育应平等而普惠
试题
类型:操作题
难度系数:0.40
所属科目:高中信息技术
小明需要根据订单的取件距离依次安排快递员取件。快递员出发后不能中途折返,但可以接更远距离的快递订单。当小明新接到一个取件订单,他会依次安排可以取件的快递员取件,若该订单距离小于所有已出发的快递员的最远距离,则安排新的快递员出发取件。编写VB程序,实现上述功能。程序运行时,在文本框Text1中输入订单距离(各数值之间用“,”隔开),单击“安排”按钮Command1后,在标签Label2中显示最后一件快递的收取情况。运行界面如图所示。

(1)运行窗体中,具有Caption属性的对象共有_______类。
(2)若快递订单的取件距离依次为“243,123,167,309,183,229,87,333,183”,则最后距离为183的订单由______号快递员收取。
(3)实现上述功能的VB程序如下,请在划线处填入合适的代码。
(4)程序加框处代码有错,请改正
Dim dd(0 To 100) As Integer           '记录所有订单的取件距离
Dim fp(0 To 100) As Integer             '存储第x个快递员取件的最远距离
Dim xs(0 To 100) As String
Private Sub Command1_Click()
Dim n As Integer,i As Integer,k As Integer,s As String
Dim left As Integer,right As Integer,m As Integer
Dim x As Integer,r As Integer
Randomize
s = Text1.Text: n = 1: i = 1
Do While i <= Len(s)
k = i: ch = Mid(s, k, 1)
Do While   _______
k = k + 1: ch = Mid(s,k,1)
Loop
dd(n) = Val(Mid(s,i,k - i))
i = k + 1: n = n + 1
Loop
x = 1: fp(x) = dd(1)
For i = 2 To n - 1
left = 1
right = x
Do While left <= right
m = (left + right) \ 2
If   ______  Then
right = m - 1
Else
left = m + 1
End If
Loop
_______
fp(r) = dd(i)
If r = x + 1 Then x = x + 1
Next i
Label2.Caption = "第" + Str(i - 1) + "件快递将由第" + Str(r) + "号快递员收取"
'列表框List1中显示每位快递员的收取情况,代码略
End Sub
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2019-09-19

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
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用户名称
2019-09-19
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