
(注:探针检测结果与上面的家系中的个体位置对应)
A.利用这两种探针能对甲、丙家系Ⅱ–2的CFTR基因进行产前诊断 |
B.乙家系中再生一个孩子,其CFTR基因正常的概率为1/4 |
C.丙家系Ⅱ–1携带两个DNA序列相同的CFTR基因 |
D.如果丙家系Ⅱ–2表型正常,用这两种探针检测出1个条带的概率为2/3 |

同类型试题

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2


y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

