A.F2出现不同尾形鱼说明该性状的遗传遵循自由组合定律 |
B.F2中雌雄鱼自由交配,其子代中深蓝尾鱼所占的比例为1/2 |
C.浅蓝尾鱼测交实验后代表型及比例是浅蓝尾∶紫尾=1∶1 |
D.F2中深蓝尾个体与浅蓝尾个体杂交,F3中不会出现紫尾个体 |

同类型试题

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2


y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

