A.A/a、B/b两对基因的遗传遵循自由组合定律,亲本基因型为AABb |
B.F1出现上述表现型及比例的原因是基因型为aB的雄配子或雌配子致死 |
C.让F1中黄色植株随机受粉,子代表现型及比例为黄色:白色=3:1 |
D.让F1中的浅紫色植株与白色植株杂交,可判断浅紫色植株的基因型 |

同类型试题

y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2


y = sin x, x∈R, y∈[–1,1],周期为2π,函数图像以 x = (π/2) + kπ 为对称轴
y = arcsin x, x∈[–1,1], y∈[–π/2,π/2]
sin x = 0 ←→ arcsin x = 0
sin x = 1/2 ←→ arcsin x = π/6
sin x = √2/2 ←→ arcsin x = π/4
sin x = 1 ←→ arcsin x = π/2

